Total no. of voids in `0.5` mole of a compound forming hexagonal closed packed structure are :

Options

A. `6.022xx10^23`
B. `3.011xx10^23`
C. `9.033xx10^23`
D. `4.516xx10^23`

Answer

C

Explanation

In hexagonal close packed structure , there are 6 atoms per unit cell
total number of voids = 6+12=18
`therefore` total number of voids per atom = `18/6=3`
`therefore` In 1 mole compound the total number of voids
`=3xx6.022xx10^23`
`therefore` In 0.5 mole compound , the total number of voids
`=3xx0.5xx6.023xx10^23`
`=9.034xx10^23`