The ionic radii of `Rb^(+)` and `I^(-)` are 1.46 and `2.16Å`. The most probable type of structure exhibited by it is:

Options

A. CsCl type
B. ZnS type
C. NaCl type
D. `CaF_2` type

Answer

C

Explanation

According to radius ratio rule,
`(r_(c^+)(Rb^+))/(r_(a)(I^-)) = (1.46)/(2.16) = 0.676`
It will have coordination number 6 and structure will be same as of NaCl