Home
Class 12
CHEMISTRY
The molar volume of KCl and NaCl are 37....

The molar volume of KCl and NaCl are `37.46` mL and `27.94`mL respectively . The ratio of the unit cube edges of the two crystals is

A

1.296

B

1.102

C

1.341

D

0.95

Text Solution

Verified by Experts

The correct Answer is:
B

`(d_(KCl))/(d_(NaCl))=((37.46)/(27.94))^(1//3)=1.102`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 2|38 Videos
  • SOLID STATE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|12 Videos
  • SOLID STATE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|12 Videos
  • S-BLOCK ELEMENTS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2|20 Videos
  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|25 Videos

Similar Questions

Explore conceptually related problems

The molar volumes of KCl and NaCl are 40 mL and 30 mL , respectively. Find the ratio of the unit cube edges of the two crystals. Assume both have the same packing efficiency.

A metal can be crystallized in both BCC and FCC unit cells whose edge lengths are 2 pm and 4 pm respectively. Then ratio of densities of FCC and BCC unit cells is

Two inflated ballons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating.

For an allotropic change: A(s)to B(s), deltaG_(400)^(@)=20kJ//"mole" If molar volume A and B are 12mL//"mole" and 10mL//"mole" respectively then calculate approximate pressure at which the two allotropes will be at equillibrium at 400K:

The edges of two cubes are 4 cm and 6 cm. Find the ratio of the volumes of the two cubes.

The edge of two cubes are 2 cm and 4 cm. Find the ratio of the volumes of the two cubes.

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-SOLID STATE-EXERCISE 1
  1. How many unit cells are present in a cube-shaped crystal of NaCl of ma...

    Text Solution

    |

  2. The pyknometric density of sodium chloride crystal is 2.165xx10^(3)kg ...

    Text Solution

    |

  3. The molar volume of KCl and NaCl are 37.46 mL and 27.94mL respectively...

    Text Solution

    |

  4. Nickle crystallise in a fcc unit cell with a cell edge length of 0.352...

    Text Solution

    |

  5. Iron crystallises in a bcc system with a lattice parameter of 2.861 Å....

    Text Solution

    |

  6. An element having an atomic radius of 0.14 nm crystallises in a fcc un...

    Text Solution

    |

  7. a metal crystallizes with a face-centered cubic lattice.The edge of th...

    Text Solution

    |

  8. AB crystallises in a bcc lattice with edge length qa equal to 387 pm.T...

    Text Solution

    |

  9. A metal crystallises in a bcc lattice ,its unit cell edge length in ab...

    Text Solution

    |

  10. If 'a' stands for the edge length of the cubic systems: simple cubic,b...

    Text Solution

    |

  11. Aluminium has fcc structure. The length of the unit cell is 409 pm. I...

    Text Solution

    |

  12. Copper crystallises in fcc with a unit cell length of 361 pm. What is ...

    Text Solution

    |

  13. Sodium crystallises in bcc arrangement with the interfacial separation...

    Text Solution

    |

  14. Which of the following point defects are shown by AgBr (s) crys...

    Text Solution

    |

  15. Due to schottky defect the density of the crystal A… whereas due to fr...

    Text Solution

    |

  16. The flame colours of metal ions are due to

    Text Solution

    |

  17. When electrons are trapped into the crystalline anion vacancy the def...

    Text Solution

    |

  18. Which is the wrong statement regarding a crystal containing Schottky d...

    Text Solution

    |

  19. What type of crystal defect is indicated in the diagram below ?

    Text Solution

    |

  20. The n-type semiconductor is obtained when Si is doped with

    Text Solution

    |