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In fcc unit cell , what is the volume oc...

In fcc unit cell , what is the volume occupied ?

A

`4/3 pir^3`

B

`8/3 pi r^3`

C

`16/3 pi r^3`

D

`(64r^3)/(3sqrt3)`

Text Solution

Verified by Experts

The correct Answer is:
C
The volume occupied by the fcc unit cell is `16/3 pi r^3`
Packing fraction or volume occupied `=(Z_(eff)xx4/3pir^3)/(a^3)`
For fcc, `Z_(eff) = 4`
`=(4xx4/3pir^3)/(a^3)` (where , a=1)

`=16/3 pir^3`
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