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A cord is wound round the circumference of a solid cylinder radius `R` and mass `M`. The axis of the cylinder is horizontal. A weight `mg` is attached to the end of the cord and falls from rest. After falling through a distance `h`.

If the mass starts from rest and falls a distance `h`, then its speed at that instant is:

A

proportional to `R`

B

proportional to `1/R`

C

propotional to `1/R^(2)`

D

independent of `R`

Text Solution

Verified by Experts

The correct Answer is:
D

`mgh=1/2(MR^(2))/2.(v^(2))/(R^(2))+1/2mv^(2)`
`4mgh=Mv^(2)=2mv^(2)implies v=sqrt((4mgh)/(M+2m))`
which is independent of `R`
`i.e., vpropR^(2)`
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