Calculate the torque developed by ann airplane engine whose output is `2000 HP` at an angular velocity of `2400 rev//min`.
Text Solution
Verified by Experts
`omega=2pi(2400/60)=80pirad//s` Work done by torque`=("torque")xx("angular displacement")` Power `=` work done per sec `=tau(/_\theta)/(/_\t)` Power `=tauomegaimplies =(2000xx746)/(80pi)=5937Nm`
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