In Fig. the velocities are in ground frame and the cylinder is performing pure rolling on the plank, velocity of point `'A'` would be

Options

A. `2V_(C)`
B. `2V_(C)+V_(P)`
C. `2V_(C)+V_(P)`
D. `2(V_(C)-V_(P))`

Answer

C

Explanation

For pure rolling velocity of te point of contact as to be equal to the velocity of the surface.
Let us say cylinder rolls with angular velocity `omega`.
At point `B`,
`V_(C)-omegar=V_(P)impliesomegar=V_(C)-V_(P)`
At point `A`
`V_(A)=V_(C)+omegar=2V_(C)-V_(P)`