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A uniform circular disc of mass M and ra...

A uniform circular disc of mass `M` and radius `R` rolls without slipping on a horizontal surface. If the velocity of its centre is `v_0`, then the total angular momentum of the disc about a fixed point `P` at a height `(3R)//2` above the centre `C`.

A

increases continuously as the disc moves away

B

decreases continuously as the disc moves away

C

is equal to `2MRv_(0)`

D

is equal to `MRv_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecL=I_(CM)vecomega=mvecrxxvecv_(CM)`
`=(MR^(2))/2omega(-hatk)+M3/2 R(-hatj)xxv_(0)hati`
`=MRv_(0)hatk`
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