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A uniform rod of mass m, length l rests ...

A uniform rod of mass `m`, length `l` rests on a smooth horizontal surface. Rod is given a sharp horizontal impulse `p` perpendicular to the rod at a distance `l//4` from the centre. The angular velocity of the rod will be

A

`(3p)/(ml)`

B

`p/(ml)`

C

`p/(2ml)`

D

`(2p)/(ml)`

Text Solution

Verified by Experts

The correct Answer is:
A
`pl/4=(ml^(2))/4omega`e
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