A rolling object rolls without slipping down an inclined plane (angle of inclination `theta`), then the minimum acceleration it can have is.
.

Options

A. `gsintheta`
B. `(2gsintheta)/3`
C. `(gsintheta)/2`
D. zero

Answer

C

Explanation

`a=(gsintheta)/(1+I(MR^(2)))`
a is minimum if `I` is maximum ltbRgt `I_("max") MR^(2)` [for ring]
`a_("min") =(gsintheta)/(1+(MR^(2))/(MR^(2)))=(gsintheta)/2`