A disc of radius `0.2 m` is rolling with slipping on a flat horizontal surface, as shown in Fig. The instantaneous centre of rotation is (the lowest contact point is `O` and centre of disc is `C`)

Options

A. `0.2 m` below `O`
B. `0.2 m` above `O`
C. `0.6 m` above `O`
D. `0.4 m` below `O`

Answer

A

Explanation

As net velocity of contact point is not zero, the disc rolls with slipping as `omega` about `IC` is the same

`omega=(v_(0))/(IO)=(v_(c))/(IC)`
`2/x=4/(x+R)` or `x=0.2m`
Velocity of `P` is given by `v_(p)=(IP)omega=sqrt(5)Rxx2/x=2sqrt(5)m//s`