Two forces of magnitude `F` are acting on a uniform disc kept on a horizontal rough surface as shown in the figure. Friction force by the horizontal surface on the disc is `nF`. Find the value of `n`.

Answer

0

Explanation

Let `f` be the friction force acting on the disc in the backward direction. Then `2F-f=ma` and `(F+f)r=Iomega`
`implies (F+f)r=1/2mr^(2)a/r`
`:.` Solving the above equation we get `f=0`