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A solid sphere rolls on a smooth horizon...

A solid sphere rolls on a smooth horizontal surface at `10 m//s` and then rolls up a smooth inclined plane of inclination `30^@` with horizontal. The mass of the sphere is `2 kg`. Find the height attained by the sphere before it stops (in `m`).

Text Solution

Verified by Experts

The correct Answer is:
7
`1/2Mv^(2)+1/2=Mgh`
`1/2Mv^(2)+1/2(2/5MR^(2))((V^(2))/(R^(2)))=Mgh`
`7/10Mv^(2)=Mgh`
`h=(7v^(2))/(10g)=(7(10)^(2))/(10(10))=7m`
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