Home
Class 11
PHYSICS
Two particles of mass 1 kg and 3 kg mov...

Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of the two particles is 2m/s, their centre of mass has a velocity of 0.5 m/s. When the relative velocity of approach becomes 3m/s, the velocity of the centre of mass is 0.75 m/s.

Text Solution

Verified by Experts

Since no external force is acting on the two particle system
`:.a_(CM)=0`
`implies V_(CM)=`constant
Promotional Banner

Topper's Solved these Questions

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS|Exercise SCQ_TYPE|29 Videos
  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS|Exercise MCQ_TYPE|14 Videos
  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS|Exercise Fill In The Blanks|7 Videos
  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS|Exercise Integer|11 Videos
  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS|Exercise Integer|16 Videos

Similar Questions

Explore conceptually related problems

Statement-1: Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of the two particles is 2 m//s , their centre of mass has a velocity of 0.5 m//s . When the relative velocity of approach becomes 3 m//s the velocity of the centre of mass is 0.75 m//s . Statement-2: The total kinetic energy as seen from ground is 1/2muv_(rel)^(2)+1/2mv_(c)^(2) and in absence of external force, total energy remains conserved.

Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of the two particles is 2m//s, their centre of mass has a velocity of 0.5 m/s. When the relative velocity of approach becomes 3 m/s. When the relative velocity of approach becomes 3m/s, the velocity of the centre of mass is 0.75 m/s.

Two particles of mass m_(1) and m_(2) , approach each other due to their mutual gravitational attraction only. Then

Two particles of mass m and M are initially at rest and infinitely separated from each other. Due to mutual interaction, they approach each other. Their relative velocity of approach at a separation d between them, is

Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :

Two partticles A and B intially at rest move towards each other under a mutual force of attraction. The instant at which velocity of A is 4v and velocity of B is 2v , the velocity of centre of mass of the system at that instant will be

Two spheres of masses 2M and M are initially at rest at a distance R apart. Due to mutual force of attraction, they approach each other. When they are at separation R//2 , the acceleration of the centre of mass of spheres would be

Two bodies of masses 2kg and 4 kg are moving with velocities 20 m/s and 10m/s towards each other due to mutual gravitational attraction . What is the velocity of their centre of mass ?