A cubical block of side L rests on a rough horizonta surface with coefficient of friction `mu`. A horizontal force F is applied on the block as shown. If the coefficient of friction is sufficiently high so that the block does not slide before toppling, the minimum force required to topple the block is

Options

A. infinitesimal
B. `mg//4`
C. `mg//2`
D. `mg(1-mu)`

Answer

C

Explanation

The applied force shifts the normal reaction to one corner as shown in figure. At this situation, the cubical block starts topping about `O`. Taking torque about `O`. We get

`FxxL=mgxxL/2`
`F=(mg)/2`