A block of base `10cmxx10cm` and height 15cm is kept on an inclined plane. The coefficient of friction between them is `sqrt3`. The inclination `theta` of this inclined plane from the horizontal plane is gradually increased from `0^@` Then

Options

A. at `theta=30^@` the block will start sliding down the plane
B. the block will remain at rest on the plane up to certain `theta` and ten it will topple
C. at `theta=60^@` the block will start slidng down the plane and continue to do so at higher angles
D. at `theta=60^@` the block will start sliding down the plane and on further increasing `theta`, it will topple at certain `theta`

Answer

B

Explanation

For sliding `tanthetagesqrt(3)(=1.732)`
For toppling `tanthetage2/3(=0.67)`