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Ler l be the moment of inertia of a uni...

Ler l be the moment of inertia of a uniform square plate about an axis AB that passes through its centre and is parallel to two of its sides. CD is a line in the plane of the plate that passes through the centre of the plate and makes an angle `theta` with AB. The moment of inertia of the plate about the axis CD is then equal to

A

`I`

B

`Isin^(2)theta`

C

`Icos^(2)theta`

D

`Icos^(2)(theta/2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`A'B'_|_ AB` and `C''D'_|_CD`
From symmetry `I_(AB)=I_(A'B)` and `I_(CD)=I_(CD)`
From theorem of perpendicular axis

`I_(zz)=I_(AB)I_(A'B')=I_(CD)+I_(CD')`
`implies 2I_(AB)=2II_(CD)`
`I_(AB)=I_(CD)`
Alternative method:
The relation between `I_(AB)` and `I_(CD)` should be true for all values of `theta`
At `theta=I_(CD)=I_(AB)`
Similarly at `theta=pi/2`
`I_(CD)=I_(AB)` (By symmetry)
Keeping these things in mind, option a is correct.
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