A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at the side. If the radius of the vessel is `5 cm` and the speed of rotation is `4 rev//s`, then the difference in the height of the liquid at the centre of the vessel and its sides is

Options

A. `8cm`
B. `2cm`
C. `40cm`
D. `4cm`

Answer

A

Explanation

Given `R=5cm, omega=2pi(4)rad//s`
Using `y=(omega^(2)x^(2))/(2g)`
the required level different is . When `x=R`,
`y=((8pi)^(2)(5xx10^(-2)))/(2xx9.8)=8cm`