A U tube is rotated about one of it's limbs with an angular velocity `omega`. Find the difference in height H of the liquid (density `rho`) level, where diameter of the tube `dlt lt L`.

Options

A. `(omega^(2)L^(2))/(2sqrt(2)g)`
B. `(omega^(2)L^(2))/(2g)`
C. `(2omega^(2)L^(2))/g`
D. `(2sqrt(2)omega^(2)L^(2))/g`

Answer

B

Explanation

`dF=dmxomega^(2)`
and `(dp)=rhoomega^(2)int_(0)^Lomegadx`
`P_(2)-P_(1)=(rhoomega^(2)L^(2))/2`
or `impliesrhogH=(rhoomega^(2)L^(2))/2`
`H=(omega^(2)L^(2))/(2g)`