In the figure, an ideal liquid flows through the tube, which is of uniform cross section. The liquid has velocities `v_(A)` and `v_(B)`, and pressures `P_(A)` and `P_(B)` at the points `A` and `B`, respectively. Then

Options

A. `v_(A)=v_(B)`
B. `v_(A)gtv_(B)`
C. `P_(A)=P_(B)`
D. `P_(B)gtP_(A)`

Answer

A, D

Explanation

As per the continuity equation `Av=`constant `v_(A)=v_(B).` As point `B` is at the lower level, hence `p_(B)gtp_(A)`.