The shear modulus for a metal is `50000 Mpa`. Suppose that a shear force of `200 N` is applied on the upper surface of a cube of this metal that is `3.0 cm` on each edge. How far will the top surface be displaced?
A
`2.67 xx 10^-7 m`
B
`4.5 xx 10^-7 m`
C
`6.0 xx 10^-7 m`
D
`1.33 xx 10^-7 m`
Text Solution
Verified by Experts
The correct Answer is:
D
Shearing strain`=/_\L//L=(F/A)S` `=2000/[L^(2)(5x10^(10))]=(4xx10^(-9))/L^(2)` Solving for `/_\L` with `L=0.030m`, we have `/_\L=1.33xx10^(-7)m=0.133mum`
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