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The shear modulus for a metal is 50000 M...

The shear modulus for a metal is `50000 Mpa`. Suppose that a shear force of `200 N` is applied on the upper surface of a cube of this metal that is `3.0 cm` on each edge. How far will the top surface be displaced?

A

`2.67 xx 10^-7 m`

B

`4.5 xx 10^-7 m`

C

`6.0 xx 10^-7 m`

D

`1.33 xx 10^-7 m`

Text Solution

Verified by Experts

The correct Answer is:
D

Shearing strain`=/_\L//L=(F/A)S`
`=2000/[L^(2)(5x10^(10))]=(4xx10^(-9))/L^(2)`
Solving for `/_\L` with `L=0.030m`, we have
`/_\L=1.33xx10^(-7)m=0.133mum`
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