A hydraulic press contains `0.25 m^(3)(250L)` of oil. Find the decrease in volume of the oil wen it is subjected to a pressure increase `/_\p=1.6xx10^(7)Pa`. The bulk modulus of the oil is `B=5.0xx10^(9)Pa`.
Text Solution
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`B=-(/_\p)/(/_\V//V_0)=-((0.25m^(3))(1.6xx10^(7)Pa))/(5.0xx10^(9)Pa)` `=-8.0xx10^(-4)m^(3)=-0.80L` Even through the pressure increase is very large, the fractional change in volume is very small. `:./_\V//V_0=(-8.0xx10^(-4)m^(3))/(0.25m^(3))=-0.0032` or `-0.32%`
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE