Compressibility of water is `5xx10^(-10)m^(2)//N`. Find the decrease in volume of `100 mL` of water when subjected to a pressure of `15 MPa`.
Text Solution
Verified by Experts
The compressibility `K` is the reciprocal of the bulk moxulus. `:/_\V=-VK/_\p` `=-((100mL)95xx10^(-10)m^(2)//N)(15xx10^(6)N//m^(2))` `=-0.75mL` The decrease in volume is thus `0.75mL`.
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
