A catapult consists of two parallel rubber strlings each of lengths, `10 cm` and cross sectional area `10mm^(2)`. Wen struetched by `5 cm`, it can throw a stone of mass `10 gm` to a vertical height of `25 m`. Determine Young's modulus of elasticity of rubber.
Text Solution
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A stretched catapult has elastic potential energy stroed in it (Strain energy stored in boty the rubber strings) `U=(1/2(YAl^(2))/L)xx2` This energy when imparted to the stone, it flies off a height `20 m`. Energy possesed by the stone `=mgh`. Now. `U=mghimplies(YAl^(2))/L=mgh` `Y=(mghL)/(Al^(2))=(1xx10^(-1)xx10xx25xx10^(-1))/(10xx10^(-6)xx(5xx10^(-2))^(2))` `:. Y=10xx10^(8)N//m^(2)`
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
