Calculate the work down against surface tension in blowing a soap bubble from a radius of `10 cm` to `20 cm`, if the surface tension of soap solution in `25xx10^(-3)N//m`.
Text Solution
Verified by Experts
Original total surface area `=2xx4pir_(1)^(2)=2xx4pixx(0.1)^(2)m^(2)` (as bubble has two surfaces). Final total surface area`=2xx4pir_(2)^(2)=2xx4pixx(0.2)^(2)m^(2)` Therefore, extension in area `=2xx4pi[(0.2)^(2)-(0.1)^(2)]=0.24pim^(2)` Now, work done `W = `surface tension `xx` extension in area `=25xx10^(-3)xx0.14pi=6pixx10^(-3)J`
Calculate the work done agains surface tension in blowing a soap bubble from a radius 10 cm to 20 cm if the surface tension of soap solution is 25xx10^(-3)N//m then compare it with liquid drop of same radius.
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
