Calculate the difference `h` in water levels in two commnicating capillary tube of radius `1 mm` and `1.5 mm`. Surface tension of water` =0.07Nm^(-1)`
Text Solution
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Pressure at `A=p_(0)+(2T)/(r_(1))` (since pressure on concave side is greater than that on convex side) Pressure at `B=p_(0)-(2T)/(r_(2))` Therefore, pressure difference `=2T(1/(r_(1))-1/(r_(2)))` Let this pressure difference correspond to `h` units of the liquid. Then `2T(1/(r_(1))-1/(r_(2)))=rhoghimpliesh=(2T)/(rhog)(1/(r_(1))-1/(r_(2)))` `:. h=(2xx0.07)/(1000xx9.8)(1/(1xx10^(-3))-1/(1.5xx10^(-3)))=4.76mm`
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
