What should be the pressure inside a small air bubble of `0.1 mm` radius situated just below the surface of water? Surface tension of water `=72xx10^(-3)N//m` and atmospheric pressure `=1.013xx10^(5)N//m^(2)`
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The excess pressure for air bubble is `p=(2T)/r` or `p=(2xx72xx10^(-3))/(0.1xx10^(-3)=1440N//m^(2)` Since the bubble is just below the water suface, the external pressue on it is equal to the atmospheric pressure `P`. Hence the pressure inside the bubble is `P+p=1.013xx10^(5)+1440=1.013+10^(5)+0.0144xx10^(5)` `=1.274xx10^(5)N//m^(3)`
What should be the pressure inside a small air bubble of 0.1mm radius situated just below the water surface. Surface tension of water =7.2xx10^(-2)N//m and atmosphere pressure =1.013xx10^(5)N//m^(2) .
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What should be the pressure inside a small air bubble of 0.2mm diameter situated just below the surface of water. ("Surface tension of water" = 0.072N//m)
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An air bubble is lying just below the surface of water. The surface tension of water is 70xx10^(-3)Nm^(-1) and atmospheric pressure is 1.013xx10^(5)Nm^(-2) . If the radius of bubble is 1mm, then the pressure inside the bubble will be-
CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
