A glass rod of diameter `d_(1)=1.5 mm` in inserted symmetricaly into a glas capillary with inside diameter `d_(2)=2.0` mm. Then the whole arrangement is vertically oriented and bruoght in contact with the surface of water. To what height will the liquid rise in the capillary? Surface tension of water `=73xx10^(-3)N//m`
Text Solution
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If `R` is radius of meniscs, then `(2T)/R=hrhog` Here `R=(r_(2)-r_(1))/(costheta)` `theta` being angle of contact `r_(1)=` radius of glass rod `r_(2)=`radius of capillary, `(2Tcostheta)/(r_(2)-r_(1))=hrhog` or `h=(2Tcostheta)/((r_(1)-r_(2))rhog)` Here `r_(1)=(d_(1))/2, r_(2)=(d_(2))/2` `:. h=(4Tcostheta)/((d_(2)-d_(1))rhog)` Substituting given values and `theta~=0^@` for water glass interface we have `h=(4xx73xx10^(-3)cos0^@)/((2.0-1.5)xx10^(-3)xx10^(3)xx9.8)=60xx10^(-3)m=6cm`
A glass rod of diameter d_1 =1.5 mm is inserted symmetrically into a glass capillary with inside diameter d_2=2 mm . Then the whole arrangement is vertically oriented and broght in contact with the surface of water . Surface tension and density of water are 0.075 N//m and 10^3 kg//m^3 respectively . the height throgh which the water will rise in the capillary is (g=10 m//s^2)
A glass rod of radius 1 mm is inserted symmetrically into a glass capillary tube with inside radius 2 mm . Then the whole arrangement is brought in contact of the surface of water. Surface tension of water is 7 xx 10^(-2) N//m . To what height will the water rise in the capillary? ( theta = 0^@ )
A glass rod of diameter d=2mm is inserted symmetrically into a glass capillary tube of radius r=2mm . Then the whole arrangement is vertically dipped into liquid having surface tension 0.072 Nm. The height to which liquid will rise on capillary is (Take g=10(m)/(s^(2)) , "density"_("liq")=1000(kg)/(m^(3))) . Assume contact angle to be zero, capillary tube to be long enough
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
