The end of a capillary tube with a radius `r` is immersed in water. Is mechanical energy conserved when the water rises in the tube? The tube is suficiently long. If not calculate the energy change.
Text Solution
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In the equilibrium position `(theta=0^@` for water and glass) `2piTcos0^@=pir^(2)hrhog` or `h=(2T)/(rhogr)` Work done by surface tension `k=(2pirT)xxh=(4piT^(2))/(rhog)` The potential energy of water in the tube `U=(pir^(2)hro)gh//2,` it is multiplied by `h//2` because the centrte of gravity of the water and the capillary tube is at a height `h//2` `:. U=(2piT^(2))/(rhog)` Thus it is seen that the mechanical energy is not conserved. therefore, mechanical enegy loss `=(4piT^(2))/(rhog)-(2piT^(2))/(rhog)=(4piT^(2))/(rhog)` This energy is converted into heat.
The end of a capillary tube with a radius r is immerseed into water. What ammount of heat will be evolved when the water rises in the tube ? If surface tension of water 'T' density of water = rho . Given (T^(2))/(rhog) = (2)/(pi) .
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CENGAGE PHYSICS-PROPERTIES OF SOLIDS AND FLUIDS-INTEGER_TYPE
