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Three rods of uniform area of cross sect...

Three rods of uniform area of cross section `A =10^(-7)m^(2)` are arranged as shown in Fig
Find out the shift in point `B, C` and `D`.

Text Solution

Verified by Experts

`/_\L_(B)=/_\L_(AB)=(FL)/(AL)=(MgL)/(AY)`
`=(10x10x0.1)/(10^(-7)xx2.5xx10^(10))=4xx10^(-3)m=4mm`
`/_\L_(C)=/_\L_(B)+/_\L_(BC)`
`=4xx10^(-3)+(10xx0.2)/(10^(-7)xx4xx10^(10))`
`/_\L_(C)=/_\L_(B)+/_\L_(BC)`
`=4xx10^(-3)+(100xx0.2).(10^(-7)x10^(-3)+5xx10^(-3))=9mm`
`=4xx10^(-3)+5xx10^(-3)=24mm`
`/_\L_(D)=/_\L_(C)+/_\L_(CD)`
`=9xx10^(-3)+(100xx0.15)/(10^(-7)xx1xx10^(10))`
`=9xx10^(-3)+15xx10^(-3)=24mm`
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