Home
Class 11
PHYSICS
A mercury drop of radius R is sprayed in...

A mercury drop of radius `R` is sprayed into `n` droplets of equal size. Calculate the energy expanded if surface tension of mercury is `T`.

Text Solution

AI Generated Solution

To solve the problem of calculating the energy expended when a mercury drop of radius \( R \) is sprayed into \( n \) droplets of equal size, we can follow these steps: ### Step 1: Calculate the Initial Surface Area The initial surface area \( A_{\text{initial}} \) of the mercury drop with radius \( R \) is given by the formula for the surface area of a sphere: \[ A_{\text{initial}} = 4 \pi R^2 \] ...
Promotional Banner

Topper's Solved these Questions

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS|Exercise Subjective|16 Videos
  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS|Exercise Single Correct|112 Videos
  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS|Exercise Exercise 5.2|6 Videos
  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS|Exercise Integer type|1 Videos
  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS|Exercise Integer|11 Videos

Similar Questions

Explore conceptually related problems

A mercury drop of radius 1 cm is sprayed into 10^(6) dropletes of equal size. Calculates the energy expanded if surface tension of mercury is 35 xx 10^(-3) N//m .

A mercury drop of radius 1.0 cm is sprayed into 10^(8) droplets of equal size. Calculate the energy expanded. (Surface tension of mercury = 32 xx 10^(-2) N//m ).

A menisus drop of radius 1 cm sprayed into 10^(5) droplets of equal size . Calculate the energy expended if surface tension of mercury is 435 xx10^(-3) N/m

A mercury drop of radius 1 cm is sprayed into 10^(6) drops of equil size. The energy expended in joule is (surface tension of mercury is (460xx10^(-3)N//m)

A mecury drop of radius 1 cm is sprayed into 10^(5) droplets of equal size. Calculate the increase in surface energy if surface tension of mercury is 35xx10^(-3)N//m .

A mercury drop of radius 1.0 cm is sprayed into 10^(6) droplets of equal sizes. The energy expended in this process is (Given, surface tension of mercury is 32 xx 10^(-2) Nm^(-1) )

What is the change in surface energy , when a mercury drop of radius R split up into 1000 droplets of radius of r ? [ The surface tension of mercury is T ]

A mercury drop of radius R splits up into 1000 droplets of equal radii . The change in the surface area is

When a mercury drop of radius R, breaks into n droplets of equal size, the radius (r ) of each droplet is