A liquid of specific gravity `1.5` is observed to rise `3.0 cm` in a capillary tube of diameter `0.50 mm` and the liquid wets the surface of the tube. Calculate the excess pressure inside a spherical bubble of `1.0 cm` diameter blown from the same liquid.

Explanation

The surface tension of liquid is
`T=(rhrog)/2`
`((0.025cm)(3.0cm)(1.5gm//cm^(3))(980cm//sec)^(2))`
`=55"dyne"//cm`
Hence excess pressure inside a spherical bubble
`/_\p=(4T)/R=(4xx55"dyne"//cm)/((0.5cm))=440dyne//cm^(2)`