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When the load on a wire is slowly increa...

When the load on a wire is slowly increased from `3` to `5 kg wt`, the elongation increases from `0.61` to `1.02 mm`. The work done during the extension of wire is

A

`0.16J`

B

`0.016J`

C

`1.6J`

D

`16J`

Text Solution

Verified by Experts

The correct Answer is:
B
Work done `= 1/2xx` stretching `xx` extension.
Therefore, net work done in increasing the length from `0.164 mm` to `1.02 mm` is
`W_(2)-W_(1)=1/2x5xx9.8xx1.02xx10^(-3)-1/2`
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