Two wires of the same material and same mass are stretched by the same force. Their lengths are in the ratio

Options

A. `3:2`
B. `2:3`
C. `4:9`
D. `9:4`

Answer

C

Explanation

`m=alp, m` and `rho` are constants
`:. (a_(1))/(a_(2))=(l_(2))/(l_(1))=3/2`
Now, `Y=(Fl)/(a/_\l)` or `/_\l propl/a`
or `(/_\l_(1))/(/_\l_(2))=(l_(1))/(l_(2))xx(a_(2))//(a_(1))=2/3xx2/3` or `(/_\l_1)/(/_\l_2)=4/9`