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The surface energy of a liquid drop is E...

The surface energy of a liquid drop is `E`. It is sprayed into `1000` equal droplets. Then its surface energy becomes

A

`1000E`

B

`100E`

C

`10E`

D

`E`

Text Solution

Verified by Experts

The correct Answer is:
C
Final surface energy `=1000xx4pir^(2)sigma`
Initial surface energy `E=4piR^(2)sigma`
Again `4/3piR^(3)=1000xx4/3pir^(2)` or `R=10r`
Now final energy
`1000xx4pir^(2)sigma=10xx4piR^(2)sigma=10E`
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