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The rate constants of a reaction at 500 ...

The rate constants of a reaction at 500 K and 700 K are `0.02 s^(-1)and 0.04 s^(-1)` respectively. Calculate the values of `E_(a)` and A.

Text Solution

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`log ""(k_(2))/(k_(1))=(E_(a))/(2.030R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`log ""(0.07)/(0.02) =((E_(a))/(2.303xx8.314 JK^(-1)mol ^(-1)))((700-500)/(700xx500))`
`0.544=E_(a) xx5.714 xx10^(-4)//19.15`
`E_(s) =0.544xx19.15//5.714xx10^(-4)`
`=18230.8J`
Since `k=Ae^(-Ea//RT)`
`0.02=Ae^(-18230.8//8.314xx500)`
`A=0.02 //0.012=161`
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