The rate constant of the chemical reaction doubled for an increase of 10 K in absolute temperature from 298 K. Calculate `E_(a)`.

The rate of the chemical reaction doubles for an increase of 10K in absolute temperature form 298 K. Calculate E_(a) .

The rate constant of a reaction is doubled when the temperature is raised from 298 K to 308 K. Calculate the activation energy.

The rate of a chemical reaction is increased in presence of a catalyst. This is because

The rate of a chemical reaction doubles for every 10^(@)C rise in temperature. If the temperature is increased by 60^(@)C the rate of reaction increases by about

The rate of reaction is generally doubled for .... rise in temperature.

For a particular reaction, the rate constant becomes double on increasing temperature from 27^(@)C to 37^(@)C. Calculate the approximate activation energy (in kcal mol^(1) R = 2 cal mol^(-1)K^(-1))

The increase in rate constant of a reaction is more when the temperature increases from

Arrhenius studied the effect of temperature on the rate of a reaction and postulated that rate constant varies with temperature exponentially as k=Ae^(-E_(a)//RT) . For most of the reactions it was found that the temperature coefficient of the reaction lies between 2 to 3. The method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied by studying how much the rate of reaction changes in the presence of catalyst. In most of the cases, it is observed that catalyst lowers the activationenergy barrier and increases the rate of reaction. If the rate oc reaction grwos 15.6 times on increasing the temperature by 30 K the temperature coefficient of the reaction will be nearly