Two point charges `+5xx10^(-19)C and +20xx10^(-19)C` are separated by a distance of 2m. The electric field intensity will be zero at a distance d=………. From the charges of `5xx10^(19)C`.

Explanation

To find the distance \( d \) from the charge \( +5 \times 10^{-19} \, C \) where the electric field intensity will be zero, we can follow these steps:

### Step 1: Understand the Setup
We have two point charges:
- \( Q_1 = +5 \times 10^{-19} \, C \) (Charge 1)
- \( Q_2 = +20 \times 10^{-19} \, C \) (Charge 2)

These charges are separated by a distance of \( 2 \, m \).
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