A charge 'Q' is distributed over two concentric hollow spheres of radii 'r' and 'R' `(gtr)` such that the surface densities are equal. Find the potential at the common centre.

Options

A. `(Q r^2)/(r^2 + R^2) and (Q R^2)/(r^2 + R^2)`. Respectively
B. `Q(1 + (r^2)/(R^2)) and Q (1 + (R^2)/(r^2))`, respectively
C. `Q(1 - (r^2)/(R^2)) and Q (1 - (R^2)/(r^2))`, respectively
D. `(Q R^2)/(r^2 + R^2) and Q (Q r^2)/(r^2 + R^2)`, respectively

Answer

A

Explanation

If `q_1` and `q_2` are the charges on the spheres of radii r and R, respectively, then by conservation of charge.
.
`q_1 + q_2 = Q` …(i)
But `sigma_(1)=sigma_(2)`
`q_(1)/(4pi r^(2))=q_(2)/(4pi R^(2))`
or `q_(1)/q_(2)=r^(2)/R^(2)`
From Eqs. (i) and (ii), we get
`q_1 = (Qr^2)/(r^2 + R^2) and q_2 = (Q R^2)/(r^2 + R^2)`
Hence, potential at common center is
`V = V_1 + V_2`
=`(1)/(4 pi epsilon_0) [q_(1)/r+q_(2)/R]`
=`(1)/(4 pi epsilon_0) [(Q r)/((R^2 + r^2))+ (Q R)/((R^2 + r^2))]`
=`(1)/(4 pi epsilon_0) (Q(R + r))/((R^2 + r^2))`.