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Find the longest and shortest wavelength...

Find the longest and shortest wavelengths in the Lyman
series for hydrogen. In what region of the electromagnetic spectrum does each
series lie?

Text Solution

Verified by Experts

The transition equation for Lyman series is given by
`(1)/(lambda) = R ((1)/(1^(2)) - (1)/(n^(2)))`. N = 2,3` ….
The largest wavelength is corresponds to `n = 2`
`:. (1)/(lambda_(max)) = 1.097 xx 10^(7)) ((1)/(1) - (1)/(4))`
`= 0.823 xx 10^(7)`
`implies lambda_(max) = 1.2154 xx 10^(7) m = 1215 Å`
The shortest wavelength corresponds to `n = oo`
`:. (1)/(lambda_(min)) = 1.097 xx 10^(7)) ((1)/(1) - (1)/(oo))`
or ` lambda_(min) = 0.911 xx 10^(-7) m = 911 Å`
Both of these wavelength lie in the ultraviolet `(UV)` region of electromagnetic spectrum. S
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