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The volume V versus temperature T graphs...

The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressure `p_1 and p_2` are as shown in Fig. It follows from the graphs that `p_1` is greater than `p_2.`

Text Solution

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`(PV)/(T)=`constant
For a particular temperature `T_(1)`
We have `pprop(1)/(V)`
Since, `V_(1)gt V_(2),p_(2) lt p_(1)`
`implies p_(1)gtp_(2)`.
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