In `overset(o+NH_(4)` and `OF_(2)` th hybridisation of central atom respectively are .

Options

A. `sp^(3),sp^(2)`
B. `sp^(3),sp^(3)`
C. `sp^(3) d,sp^(3) ,d`
D. `sp^(3) d ,sp^(3)`

Answer

B

Explanation

Hybridisation of `overset(o+)NH_(4) implies (1)/(2) (5 + 4 -1) =4 =sp^(3)`
Hybridisation of `:overset(..)OF_(2) = (1)/(2) (6 +2) = 4 = sp^(3)` .