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If logax=alpha,logbx=beta,logc x=gamma ...

If `log_ax=alpha,log_bx=beta,log_c x=gamma` and `log_d x=delta ,xne1` and a,b,c,`dne1`,then `log_(abcd)` x equals

A

`le(alpha+beta+gamma+delta)/16`

B

`ge (alpha+beta+gamma+delta)/16`

C

`1/(alpha^(-1)+beta^(-1)+gamma^(-1)+delta^(-1))`

D

`1/(alphabetagammadelta)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
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