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If matrix A = [a(ij)](3xx3), matrix B= ...

If matrix `A = [a_(ij)]_(3xx3), ` matrix `B= [b_(ij)]_(3xx3)` where
`a_(ij) + a_(ij)=0 and b_(ij) - b_(ij) = 0` then `A^(4) cdot B^(3) ` is

A

skew- symmetric matrix

B

singular

C

symmetric

D

Both B & C

Text Solution

Verified by Experts

The correct Answer is:
D
Since, A is skew-symmetric.
`therefore abs(A)=0`
`rArr abs(A^(4) B^(3)) = abs(A^(4)) abs(B^3) = abs(A)^(4) abs(B)^(3) = 0`
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