The amount of gas produced after the tre...

The amount of gas produced after the treatment of `21.8` gm of (D) with `MeMgBr` is:

`3.2` gm

`32.0` gm

`1.6` gm

`1.06` gm

Verified by Experts

The correct Answer is:

(D) `overset(MeMgBr)rarr CH_(4)` +

(Molecular mass of (D) `= C_(15)H_(22)O = 218`)
1 mol of (D) (218 gm) `implies` 1 mol of `CH_(4) = 16` gm
`21.8` gm `implies (16xx21.8)/(218)=1.6 gm`

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