Find out which statement is correct.

Options

A. Path I proceeds by nucleophilic addition `(HOO^(Θ))` on the `(C=C)` bond followed by Michael addition with (A) to give `alpha`-carbanion which displaces `overset(Θ)(OH)` form `(HOO)` group to give epoxide (B).
B. Path II proceeds by electrophilic addition `(overset(Θ)(OH))` on the `(C=C)` bond followed by the removal of H from `(OH)` by nucleophile `(RCOO^(Θ))` to give epoxide (B).
C. Path I is faster since it proceeds by the formation of resonance-stabilised `alpha`-carbanion as shown.

D. Path II is faster since it proceeds by the formation of epoxide ion

Answer

A, B, C