Home
Class 12
CHEMISTRY
Calaulate the average molecules mass of ...

Calaulate the average molecules mass of a polymer sample in which`30%`molecules have a molecular mass of`20,000,40%`have`30,000`,and the rest`30%`have`60,000`

Text Solution

Verified by Experts

`Mbar(n)`and`Mbar(w)`of this sample will be
`Mbar(n)=((30xx20,000)+(40xx30,000)+(30xx60,000))/(30+40+30)`
`=36000`
`Mbar(w)=(30(20,000)^(2)+40(30,000)^(2)+30(60,000)^(2))/(30xx20,000+40xx30,000+30xx60,000)`
`=43333`
Promotional Banner

Topper's Solved these Questions

  • SYNTHETIC AND NATURAL POLYMERS

    CENGAGE CHEMISTRY|Exercise Solved Example|6 Videos

  • SYNTHETIC AND NATURAL POLYMERS

    CENGAGE CHEMISTRY|Exercise Exercises Concept Application|20 Videos

  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the average molecular mass of a polymer sample in which 30% molecules have a molecular mass 20,000, 40% have 30,000, and rest have 60,000. Strategy: Work out number average molecular mass (overline(M_(n))) as well as weight average molecular mass (bar(M_(w)))

A polymeric sample in which 30% molecules have a molecules mass 20,000 ,40%, have 30,000 and the rest 30% have 60,000 .The (Mbar(n)) and(Mbar(w)) of this sample was:

In a polymer sample, 30% molecules have molecular mass 20000, 40% have molecular mass 30000 and the rest 30% have 60000. Calculate their number average and mass average molecular masses.

In a polymer sample, 30% of molecules have a molecualr mass of 20,000, 40% have 30,000 and the rest 60,000. What is the weight average molecular mass of the polymer?

In a polymer sample 30% molecules have a molecular mass 20,000 , 40% have molecular mass 30,000 and rest have 60,000 .The number average molecular mass is x times10^(4) then x is

A sample of polymer contains 30% molecules with a molecular mass 20,000 , 40% with molecular mass 30,000 and 30 % with 60,000 ." .What is the number average molecular mass of the polymer?