For a process, entropy change of a system is expressed as

Options

A. H- TS
B. `(q_(rev))/T`
C. `T/(q_(rev))`
D. `q_(rev)xxT`

Answer

B

Explanation

For an isothermal reversible process, let the system absorbs q amount of heat from surroundings at temperature T. Thus, the entropy change of system will be `DeltaS_("System")=(q_(rev))/T`.