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If square of x varies as cube of y and x...

If square of x varies as cube of y and `x=3` when `y=4`, the value of y at `(1)/(sqrt3)` will be..

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`x^2propy^3`
`x^2=ky^3`
when `x=3` and `y=4`
`9=k`.`64impliesk=(9)/(64)`
`implies^3=(x^2)/(k)=(1)/(3xx9)xx64impliesy^3=(4^3)/(3^3)impliesy=(4)/(3)
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