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The magnitudes of vectors vecA,vecB and ...

The magnitudes of vectors `vecA,vecB and vecC` are 3,4 and 5 units respectively. If `vecA+vecB= vecC`, the angle between `vecA` and `vecB` is

A

`(pi)/2`

B

`cos^(-1)(0.6)`

C

`tan^(-1)(7/5)`

D

`(pi)/4`

Text Solution

Verified by Experts

The correct Answer is:
A
`C= sqrt(A^(2)+B^(2))`
`=sqrt(3^(2)+4^(2))= 5`
`:.` Angle between `vecA` and `vecB` is `(pi)/(2)`
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